* Regexp replace on all arguments.
@ 2006-02-11 17:36 Ligesh
2006-02-11 17:38 ` Stephane Chazelas
0 siblings, 1 reply; 4+ messages in thread
From: Ligesh @ 2006-02-11 17:36 UTC (permalink / raw)
To: Zsh-workers
Hi folks,
I want to replace all occurrences of say '/c/' in the arguments with 'c:'. Could someone help me with completing the function below.
winexec () {
// First loop through all arguments and replace
foreach arguments $2 to $- {
replace ^/c/ with c: , ^/d/ with d: etc. (The character c, d should be preserved, '^' means beginning of the word.)
}
execute $1 with the new arguments.
}
The execution would be
$ winexec cacls.exe /c/name-of-file
Now the function should change it to:
$ calcs.exe c:/name-of-file
Thanks in advance.
^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: Regexp replace on all arguments.
2006-02-11 17:36 Regexp replace on all arguments Ligesh
@ 2006-02-11 17:38 ` Stephane Chazelas
2006-02-11 18:21 ` Ligesh
0 siblings, 1 reply; 4+ messages in thread
From: Stephane Chazelas @ 2006-02-11 17:38 UTC (permalink / raw)
To: Zsh-workers
On Sat, Feb 11, 2006 at 11:06:26PM +0530, Ligesh wrote:
>
> Hi folks,
>
> I want to replace all occurrences of say '/c/' in the arguments with 'c:'. Could someone help me with completing the function below.
>
> winexec () {
>
> // First loop through all arguments and replace
>
> foreach arguments $2 to $- {
> replace ^/c/ with c: , ^/d/ with d: etc. (The character c, d should be preserved, '^' means beginning of the word.)
> }
>
> execute $1 with the new arguments.
>
> }
>
> The execution would be
>
> $ winexec cacls.exe /c/name-of-file
[...]
winexec() {
local cmd=$1
shift || return
argv=("${@//#\/(#b)([a-zA-Z])\//$match:}")
"$cmd" "$@"
}
--
Stéphane
^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: Regexp replace on all arguments.
2006-02-11 17:38 ` Stephane Chazelas
@ 2006-02-11 18:21 ` Ligesh
2006-02-11 19:20 ` Bart Schaefer
0 siblings, 1 reply; 4+ messages in thread
From: Ligesh @ 2006-02-11 18:21 UTC (permalink / raw)
To: Zsh-workers
On Sat, Feb 11, 2006 at 05:38:19PM +0000, Stephane Chazelas wrote:
> winexec() {
> local cmd=$1
> shift || return
> argv=("${@//#\/(#b)([a-zA-Z])\//$match:}")
> "$cmd" "$@"
> }
>
I couldn't get it to work. There is no substitution happening at all. I am getting the same arguments.
winexec cacl.exe /c/name-fo-file
gives: cacls.exec /c/name-of-file.
I am sure the code is the right direction, and but there is some silly bug which makes it fail. I am actually used to vim/emacs syntax for string substitution, but I found the zsh syntax to be a bit exotic. Especially since zsh has SO many special cases. So if you could explain the above, I would be able to correct it myself.
argv=("${@//#\/(#b)([a-zA-Z])\//$match:}")
I take it that the first '@' stands for all arguments.
What's the /#?
what's (#b)?
([a-zA-Z]) stands for 1 character, enclosed in a paranthesis for its use in the replace regexp.
Thanks.
^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: Regexp replace on all arguments.
2006-02-11 18:21 ` Ligesh
@ 2006-02-11 19:20 ` Bart Schaefer
0 siblings, 0 replies; 4+ messages in thread
From: Bart Schaefer @ 2006-02-11 19:20 UTC (permalink / raw)
To: Zsh-workers
On Feb 11, 11:51pm, Ligesh wrote:
> Subject: Re: Regexp replace on all arguments.
>
> On Sat, Feb 11, 2006 at 05:38:19PM +0000, Stephane Chazelas wrote:
> > winexec() {
> > local cmd=$1
> > shift || return
> > argv=("${@//#\/(#b)([a-zA-Z])\//$match:}")
> > "$cmd" "$@"
> > }
> >
>
> I couldn't get it to work. There is no substitution happening at all.
winexec () {
setopt localoptions extendedglob
local cmd=$1
shift || return
argv=("${@//#\/(#b)([a-zA-Z])\//$match:}")
"$cmd" "$@"
}
> What's the /#?
You're parsing it wrong.
@ The variable to expand
// Replace all occurrences of
#\/(#b)([a-zA-Z])\/ this pattern
/ with
$match: this expansion (see "backreference" below)
> what's (#b)?
The pattern is
# Anchor at beginning
\/ a slash
(#b) activate "backreferences"
([a-zA-Z]) create a backreference to one alphabetic
\/ another slash
The backreference stuff requires extendedglob. It's actually not
useful to use the // for replace-all because there can only be one
match when anchored at the beginning, so just ${@/#.../...} would
have been OK.
(This question really should have been asked on zsh-users.)
^ permalink raw reply [flat|nested] 4+ messages in thread
end of thread, other threads:[~2006-02-11 19:20 UTC | newest]
Thread overview: 4+ messages (download: mbox.gz / follow: Atom feed)
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2006-02-11 17:36 Regexp replace on all arguments Ligesh
2006-02-11 17:38 ` Stephane Chazelas
2006-02-11 18:21 ` Ligesh
2006-02-11 19:20 ` Bart Schaefer
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