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From: ZyX <zyx@np.by>
Reply-To: zyx@np.by
To: zsh-workers@zsh.org
Subject: Re: unknown file attribute
Date: Sat, 2 Apr 2011 23:32:59 +0400
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Reply to message =ABunknown file attribute=BB,=20
sent 22:33:19 02 April 2011, Saturday
by Manfred Lotz:

These are glob qualifiers: qualifiers `B' and `C' do not exist (that is why=
 you=20
see this error), but qualifier `A' means `group-readable files' and `D' mea=
ns=20
`set GLOB_DOTS option for the current pattern'. As there is no pattern then=
 no=20
files match it and zsh will behave according to its options:
1. If nullglob is set unmatched pattern is removed from argumnents list and
   `echo (A)' yields just a single newline.
2. If cshnullglob and nomatch are unset unmatched pattern is left as-is and
   `echo (A)' yields `(A)\n'
3. If either cshnullglob or nomatch are set then unmatched pattern prevents=
=20
command from executing and `echo (A)' will yield an error (either `zsh: no=
=20
matches found: (A)' if cshnullglob is unset or `zsh: nomatch' if it is set).

I suggest you to learn this glob quilifiers as they are really useful in so=
me=20
situations.

Original message:
> Hi there,
> I accidentally found that:
>=20
> $ echo (B)
>=20
> yields:
>=20
> zsh: unknown file attribute
>=20
>=20
> Same for echo (C). However, echo (A) and echo (D) work. Any idea why
> that happens?
>=20
> I know I could type: "(B)". But I want to save typing the "s.

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