Why doesn't it exit the shell?
 $ set -e
 $ echo $(false)
 Shouldn't the error code of $(false) command substitution be checked by set -e before passing stdout to the echo builtin?
 Isn't it the most logical behavior that most people would expect of set -e?
 Zsh version: zsh 4.3.17 (x86_64-redhat-linux-gnu) (if it matters)
 Thanks