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Date: Mon, 24 Sep 2018 11:22:18 +0100
From: Peter Stephenson <p.stephenson@samsung.com>
To: Klaus Alexander Seistrup <klaus@seistrup.dk>, Zsh Workers
	<zsh-workers@zsh.org>
Subject: Re: BUG: Shell builtin `which` prints non-existent commands to
 stdout
In-Reply-To: <20180924080031.ee7lqmthxpmvqaal@klaus.seistrup.dk>
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References: <CGME20180924080113epcas4p4f8f89aa03a2cebc5030fd45dca0f6e84@epcas4p4.samsung.com>
	<20180924080031.ee7lqmthxpmvqaal@klaus.seistrup.dk>

On Mon, 24 Sep 2018 10:00:31 +0200
Klaus Alexander Seistrup <klaus=40seistrup.dk> wrote:
> TL;DR: When =60which=60 does not find a command it prints the error to=20
> standard output instead of standard error. Exit code is set correctly,=20
> though, and error messages about =E2=80=98bad=20options=E2=80=99=20are=20=
sent=20to=20standard=20=0D=0A>=20error=20as=20expected.=0D=0A=0D=0AThis=20i=
s=20not=20a=20bug=20and=20has=20been=20discussed=20numerous=20times,=20e.g.=
=20the=20thread=0D=0Athat=20starts=20at.=0D=0A=0D=0Ahttp://www.zsh.org/mla/=
workers//2015/msg02253.html=0D=0A=0D=0A(official=20zsh-workers=20message=20=
number=2036330).=0D=0A=0D=0AWe=20definitely=20don't=20wish=20to=20change=20=
this=20now.=0D=0A=0D=0Apws=0D=0A