* $RANDOM initial state doesn't change
@ 2015-02-23 20:22 Timo Sirainen
2015-02-23 23:27 ` Jan Larres
0 siblings, 1 reply; 3+ messages in thread
From: Timo Sirainen @ 2015-02-23 20:22 UTC (permalink / raw)
To: zsh-workers
I was trying to use $RANDOM for a simple 1/0 check, but it kept failing. After a while I realized a new subshell always gives the same $RANDOM result:
% for i in {1..10}; do echo `echo $RANDOM`; sleep 1; done
13490
13490
13490
13490
13490
13490
13490
13490
13490
13490
Surely it should be more random than that?
Tested with:
zsh 5.0.7 (x86_64-pc-linux-gnu)
zsh 5.0.2 (x86_64-apple-darwin12.2.0)
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: $RANDOM initial state doesn't change
2015-02-23 20:22 $RANDOM initial state doesn't change Timo Sirainen
@ 2015-02-23 23:27 ` Jan Larres
2015-02-24 2:08 ` Mikael Magnusson
0 siblings, 1 reply; 3+ messages in thread
From: Jan Larres @ 2015-02-23 23:27 UTC (permalink / raw)
To: zsh-workers
On 24/02/15 09:22, Timo Sirainen wrote:
> I was trying to use $RANDOM for a simple 1/0 check, but it kept failing.
> After a while I realized a new subshell always gives the same $RANDOM
> result:
>
> % for i in {1..10}; do echo `echo $RANDOM`; sleep 1; done
> 13490
> 13490
> 13490
> 13490
> 13490
> 13490
> 13490
> 13490
> 13490
> 13490
>
> Surely it should be more random than that?
>From the manual:
RANDOM <S>
A pseudo-random integer from 0 to 32767, newly generated each
time this parameter is referenced. The random number generator
can be seeded by assigning a numeric value to RANDOM.
The values of RANDOM form an intentionally-repeatable
pseudo-random sequence; subshells that reference RANDOM will
result in identical pseudo-random values unless the value of
RANDOM is referenced or seeded in the parent shell in between
subshell invocations.
$ for i in {1..10}; do echo $(echo $RANDOM) $RANDOM; done
30686 30686
8933 8933
4452 4452
6983 6983
21425 21425
27288 27288
18721 18721
22501 22501
1008 1008
29465 29465
-Jan
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: $RANDOM initial state doesn't change
2015-02-23 23:27 ` Jan Larres
@ 2015-02-24 2:08 ` Mikael Magnusson
0 siblings, 0 replies; 3+ messages in thread
From: Mikael Magnusson @ 2015-02-24 2:08 UTC (permalink / raw)
To: Jan Larres; +Cc: zsh workers
On Tue, Feb 24, 2015 at 12:27 AM, Jan Larres <jan@majutsushi.net> wrote:
> On 24/02/15 09:22, Timo Sirainen wrote:
>> I was trying to use $RANDOM for a simple 1/0 check, but it kept failing.
>> After a while I realized a new subshell always gives the same $RANDOM
>> result:
>>
>> % for i in {1..10}; do echo `echo $RANDOM`; sleep 1; done
>> 13490
>> 13490
>> 13490
>> 13490
>> 13490
>> 13490
>> 13490
>> 13490
>> 13490
>> 13490
>>
>> Surely it should be more random than that?
>
> From the manual:
>
> RANDOM <S>
> A pseudo-random integer from 0 to 32767, newly generated each
> time this parameter is referenced. The random number generator
> can be seeded by assigning a numeric value to RANDOM.
>
> The values of RANDOM form an intentionally-repeatable
> pseudo-random sequence; subshells that reference RANDOM will
> result in identical pseudo-random values unless the value of
> RANDOM is referenced or seeded in the parent shell in between
> subshell invocations.
>
>
> $ for i in {1..10}; do echo $(echo $RANDOM) $RANDOM; done
> 30686 30686
> 8933 8933
> 4452 4452
> 6983 6983
> 21425 21425
> 27288 27288
> 18721 18721
> 22501 22501
> 1008 1008
> 29465 29465
You can use anonymous functions to always evaluate $RANDOM in the
parent shell (unless of course the whole loop is subshelled),
% for i in {1..10}; do () { echo $(echo $1) $2 } $RANDOM $RANDOM; done
--
Mikael Magnusson
^ permalink raw reply [flat|nested] 3+ messages in thread
end of thread, other threads:[~2015-02-24 2:08 UTC | newest]
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2015-02-23 20:22 $RANDOM initial state doesn't change Timo Sirainen
2015-02-23 23:27 ` Jan Larres
2015-02-24 2:08 ` Mikael Magnusson
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