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* [BUG] test ! "-o" ([ ! -o ]) exit status should be 1
@ 2021-08-09 10:55 koichi nakashima
  2021-08-09 14:16 ` Peter Stephenson
  0 siblings, 1 reply; 3+ messages in thread
From: koichi nakashima @ 2021-08-09 10:55 UTC (permalink / raw)
  To: zsh-workers

In the following code, I expected the exit status to be 1.
However, in zsh 5.0.3 and later, it was actually 0.

$ zsh -c '[ ! -o ]; echo "$ZSH_VERSION: $?"'
4.3.17: 1
$ zsh -c '[ ! -o ]; echo "$ZSH_VERSION: $?"'
5.0.0: 1
$ zsh -c '[ ! -o ]; echo "$ZSH_VERSION: $?"'
5.0.2: 1
$ zsh -c '[ ! -o ]; echo "$ZSH_VERSION: $?"' # <===
5.0.3: 0
$ zsh -c '[ ! -o ]; echo "$ZSH_VERSION: $?"'
5.8: 0

I checked the release notes, and it does not appear to be
an intentional change.


In other latest shells, it is as expected.
$ dash -c '[ ! -o ]; echo $?'
1
$ bash -c '[ ! -o ]; echo $?'
1
$ ksh -c '[ ! -o ]; echo $?'
1
$ yash -c '[ ! -o ]; echo $?'
1


^ permalink raw reply	[flat|nested] 3+ messages in thread

end of thread, other threads:[~2021-08-10  8:21 UTC | newest]

Thread overview: 3+ messages (download: mbox.gz / follow: Atom feed)
-- links below jump to the message on this page --
2021-08-09 10:55 [BUG] test ! "-o" ([ ! -o ]) exit status should be 1 koichi nakashima
2021-08-09 14:16 ` Peter Stephenson
2021-08-10  8:21   ` Peter Stephenson

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