BUG? Zsh does not print the last line of stdout of a child process if that line does not have newline char at end. BUG?

BUG? Zsh does not print the last line of stdout of a child process if that line does not have newline char at end. BUG?

[Batalov, Denis]

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I have encountered unexpected zsh behaviour which looks like a bug. At the same time it is so basic that others must have seen it before, so maybe it's not. I would appreciate some clarification.

Basically, if the last line in the output of a command executed from the zsh command-line does not have the terminating newline character, then the line is not shown by zsh. Here is a simple test one can try:

$ echo -n gogi
$

On other shells, e.g. bash, the behaviour is as expected:

$ echo -n gogi
gogi$

Any comments? Please CC directly to my e-mail address, as I am not a regular reader.

Thanks,
--
Denis V. Batalov

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Re: BUG? Zsh does not print the last line of stdout of a child process if that line does not have newline char at end. BUG?

[Wayne Davison]

On Thu, Apr 28, 2005 at 02:51:13PM -0700, Batalov, Denis wrote:
> $ echo -n gogi
> $

I like the precmd solution mentioned in the FAQ:

http://zsh.sunsite.dk/FAQ/zshfaq03.html#l40

(Note to FAQ maintainer: the index appears to be off by one -- it
linked to l39, but the answer appears to be l40.)

..wayne..

Re: BUG? Zsh does not print the last line of stdout of a child process if that line does not have newline char at end. BUG?

[Alexey Tourbin]

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On Thu, Apr 28, 2005 at 02:51:13PM -0700, Batalov, Denis wrote:
> $ echo -n gogi
> $
> 
> On other shells, e.g. bash, the behaviour is as expected:
> 
> $ echo -n gogi
> gogi$
> 
> Any comments? Please CC directly to my e-mail address, as I am not a regular reader.

setopt NO_PROMPTCR


> Thanks,
> --
> Denis V. Batalov

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