From: "Bart Schaefer" <schaefer@brasslantern.com>
To: Zoltan Hidvegi <hzoli@frontiernet.net>,
zsh-workers@math.gatech.edu (Zsh hacking and development)
Subject: Re: RC_EXPAND_PARAM final patch
Date: Sat, 2 Aug 1997 12:28:13 -0700 [thread overview]
Message-ID: <970802122813.ZM5067@candle.brasslantern.com> (raw)
In-Reply-To: <199708020727.DAA03172@hzoli.home>
On Aug 2, 3:27am, Zoltan Hidvegi wrote:
} Subject: RC_EXPAND_PARAM final patch
}
} There is still one point where the behaviour might be surprising: that's
} when the (e) substitution flag is used:
}
} % echo ${x}1${(e)^a}2${x}
} x y1a2x y y1b2x y
I get very strange behavior from this. Vis:
zagzig<25> a=('$[i++]' '$[i++]' '$[i++]')
zagzig<26> i=0
zagzig<27> echo ${^x}1${a}2${^x}
x1$[i++] y1$[i++] z1$[i++] $[i++] $[i++]2x $[i++]2y $[i++]2z
OK so far, but:
zagzig<28> i=0
zagzig<29> echo ${^x}1${(e)a}2${^x}
x10 y10 z10 $[i++] $[i++]2${^x}
Huh? Why didn't it evaluate the second ${^x}, which is unquoted and at
the same (re)interpretation level as the first ${^x} ? I would at least
have expected to get
x10 y10 z10 $[i++] $[i++]2x $[i++]2y $[i++]2z
--
Bart Schaefer Brass Lantern Enterprises
http://www.well.com/user/barts http://www.brasslantern.com
next prev parent reply other threads:[~1997-08-02 19:42 UTC|newest]
Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top
1997-08-02 7:27 Zoltan Hidvegi
1997-08-02 19:28 ` Bart Schaefer [this message]
1997-08-04 14:28 ` Andrej Borsenkow
1997-08-04 16:02 ` Peter Stephenson
1997-08-04 17:21 ` Zoltan T. Hidvegi
1997-08-04 18:39 ` Bart Schaefer
1997-08-04 18:51 ` Zoltan T. Hidvegi
1997-08-04 19:10 ` Bart Schaefer
1997-08-06 12:27 ` Andrej Borsenkow
1997-08-07 3:53 ` Zoltan T. Hidvegi
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