The following script prints "done 1"

set -e
> false && true
> echo done $?


If a statement followed by an always-block always behaves as if the
always-block wasn't there, then the following script should print the same
(after "ALWAYS")

set -e
> { false && true } always { echo ALWAYS }
> echo done $?


The current Zsh only prints "ALWAYS", while the patched one prints "ALWAYS"
followed by "done 1". So I guess that even the always patch can be
qualified as a bug fix.

Philippe


On Thu, Dec 1, 2022 at 9:05 PM Bart Schaefer <schaefer@brasslantern.com>
wrote:

> On Thu, Dec 1, 2022 at 11:30 AM Philippe Altherr
> <philippe.altherr@gmail.com> wrote:
> >
> > The patch about the always statement makes it behave like compound
> statements.
>
> A statement followed by an always-block should always behave as if the
> always-block wasn't there, except in the TRY_BLOCK_ERROR cases
> mentioned in the description of "always".  I suppose your patches
> should be tested against that.
>