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Fri, 16 Apr 2021 13:05:24 -0700 (PDT) MIME-Version: 1.0 References: <20210307171712.GA9936@tarpaulin.shahaf.local2> <20210416195028.GE15670@tarpaulin.shahaf.local2> In-Reply-To: <20210416195028.GE15670@tarpaulin.shahaf.local2> From: Bart Schaefer Date: Fri, 16 Apr 2021 13:05:13 -0700 Message-ID: Subject: Re: zmathfunc: min, max, sum throw error if result equals 0 To: Daniel Shahaf Cc: Zsh hackers list Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable X-Seq: 48607 Archived-At: X-Loop: zsh-workers@zsh.org Errors-To: zsh-workers-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-workers-request@zsh.org X-no-archive: yes List-Id: List-Help: List-Subscribe: List-Unsubscribe: List-Post: List-Owner: List-Archive: On Fri, Apr 16, 2021 at 12:51 PM Daniel Shahaf wro= te: > > [...] the first one interpolates $arg as in double-quoted strings > and then parses the string " x +=3D 2 > result ", where the > operator ha= s > higher precedence, and =C2=AB2 > result=C2=BB evaluates to 1, and the =C2= =ABprint=C2=BB then > evaluates everything left to right; whereas the latter sees =C2=ABarg=C2= =BB and > tries to evaluate that _as a number_, which works out to 2 (with a side > effect), so the condition evaluates to true, and the assignment on the > RHS then works out to 4 (with a side effect). Clear as a cloudless day Given that, I'm puzzled why you did > + (( $arg < result )) > + case $? in > + (0) result=3D$arg;; > + (1) ;; > + (*) return $?;; > + esac > done > (( result )) and why not (( arg < result )) case $? in (0) (( result =3D arg ));; (1) ;; (*) return $?;; esac done (( result )) ?? The (( $arg < result )) formulation still potentially has different operator precedence in and out of math context, and result=3D$arg followed by (( result )) still does repeat interpretation of $arg. Why ever interpolate $arg as a string?