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References: <alpine.LN8.2.00.1203091332580.1456@ckhb06.ckhb.org>
Date: Fri, 9 Mar 2012 23:25:25 +0100
Message-ID: <CAHYJk3R6P90wpqgKgxyuAp15RrR=RTxTL1XKBGz-WJF9+SBtng@mail.gmail.com>
Subject: Re: parameter expansion, substitution
From: Mikael Magnusson <mikachu@gmail.com>
To: "S. Cowles" <scowles@ckhb.org>
Cc: zsh-workers@zsh.org
Content-Type: text/plain; charset=UTF-8

On 9 March 2012 23:03, S. Cowles <scowles@ckhb.org> wrote:
> i am not getting expected results in the following code snippet:
>        b="abc" ; b=${b/#abc%/d} ; echo ${b}
> i expect the value of b to be changed to "d"; however, it remains "abc".
>
> the following snippet does give the expected result:
>        b="abc" ; b=${b/#abc/d} ; echo ${b}
>
> for this session, the following shell options are set: interactive monitor
> shinstdin zle.  the version of the shell being used is 4.3.17-dev-0,
> patchlevel 1.5604.
>
> in my use case, i need to specify a pattern match at the end of the
> parameter.  have i misunderstood the syntax of the '%' end-of-string
> operator?  or is this problem something else?
>
> thanks for any help.

It's possibly a bit counterintuitive, but both # and % go at the start
of the string, so you want
b=${b/#%abc/d}

-- 
Mikael Magnusson