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From: Sebastian Gniazdowski <sgniazdowski@gmail.com>
Date: Mon, 28 May 2018 16:43:58 +0200
Message-ID: <CAKc7PVA1bDLRsFiZgukbuY+KaD-vAaSMLpNsPzPQt15H4L89Fw@mail.gmail.com>
Subject: (z) flag little crazy when '((' closed with *single* ')'
To: Zsh hackers list <zsh-workers@zsh.org>
Content-Type: text/plain; charset="UTF-8"

Hello,
so how is (( ... )) splitted by (z)?

~ buf='(( i = 1, i <= size, ++ i ))'; printf "|%s|\n" "${(z)buf}"
|(( i = 1, i <= size, ++ i ))|

~ buf='(( i = 1, i <= size, ++ i'; printf "|%s|\n" "${(z)buf}"
|(( i = 1, i <= size, ++ i|

OK, but look what happens when there is single ')', not 0, not 2, but
1 closing parenthesis:

~ buf='(( i = 1, i <= size, ++ i )'; printf "|%s|\n" "${(z)buf}"
|(|
|(|
|i|
|=|
|1,|
|i|
|<|
|=|
|size,|
|++|
|i|
|)|

It splits almost char by char. I wonder if this couldn't be fixed? So
that (z) would split this as:

|(( i = 1, i <= size, ++ i )|

-- 
Best regards,
Sebastian Gniazdowski