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From: Sebastian Gniazdowski <sgniazdowski@gmail.com>
To: Roman Perepelitsa <roman.perepelitsa@gmail.com>
Cc: Zsh hackers list <zsh-workers@zsh.org>
Subject: Re: $+var and (P) flag
Date: Fri, 31 May 2019 13:00:20 +0200	[thread overview]
Message-ID: <CAKc7PVB4cyRvjPn_YT6eofV+Uke2cOA=k51ZV0vvAPpi4VSJ9g@mail.gmail.com> (raw)
In-Reply-To: <CAN=4vMp3mgYE766yDKq4G=n0wj0zKdZ-5iV3_W0NuRo2CC-_sA@mail.gmail.com>

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Thanks!

pon., 27 maj 2019, 21:52 użytkownik Roman Perepelitsa <
roman.perepelitsa@gmail.com> napisał:

> You can try [[ -v ${varname:1} ]] and (( $+parameters[${varname:1}] )).
>
> ${varname:1} removes the leading plus. If you can change your code so that
> the plus isn't added, it gets simpler.
>
> Roman.
>
> On Mon, May 27, 2019 at 9:46 PM Sebastian Gniazdowski <
> sgniazdowski@gmail.com> wrote:
>
>> Hello,
>> simple test:
>>
>> a=1
>> varname='+a'
>> echo ${(P)varname}
>>
>> yields empty output. Is there any way to use the $+var syntax with (P)
>> flag?
>>
>> --
>> Sebastian Gniazdowski
>> News: https://twitter.com/ZdharmaI
>> IRC: https://kiwiirc.com/client/chat.freenode.net:+6697/#zplugin
>> Blog: http://zdharma.org
>>
>

      reply	other threads:[~2019-05-31 11:01 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2019-05-27 19:45 Sebastian Gniazdowski
2019-05-27 19:52 ` Roman Perepelitsa
2019-05-31 11:00   ` Sebastian Gniazdowski [this message]

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