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Subject: Why zsh chose to be non-compliant in pattern matching
From: Cuong Manh Le <cuong.manhle.vn@gmail.com>
To: zsh-workers@zsh.org
Content-Type: multipart/alternative; boundary=001a11443e4abe3eba052ca1db32

--001a11443e4abe3eba052ca1db32
Content-Type: text/plain; charset=UTF-8

POSIX documentation for pattern matching (
http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_13_01)
said that any quoted characters in pattern will be match literally.

AFAICT, `["!"a]` will match `!` or `a`, most of shell behave like that
except zsh (and also ksh):

case a in ["!"a]) echo 1;; esac


print nothing. While:

case b in ["!"a]) echo 1;; esac


print 1. zsh treats `["!"a]` the same as `[!a]`.

Is there any reason for this behavior?

PS: The full question can be seen here
http://unix.stackexchange.com/q/265431/38906

Thanks.

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