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From: Roman Perepelitsa <roman.perepelitsa@gmail.com>
To: Sebastian Gniazdowski <sgniazdowski@gmail.com>
Cc: Zsh hackers list <zsh-workers@zsh.org>
Subject: Re: $+var and (P) flag
Date: Mon, 27 May 2019 21:52:21 +0200	[thread overview]
Message-ID: <CAN=4vMp3mgYE766yDKq4G=n0wj0zKdZ-5iV3_W0NuRo2CC-_sA@mail.gmail.com> (raw)
In-Reply-To: <CAKc7PVDp3rKdjrzXeHxiqC15TBSfbgG-rc-t6_p1=3FPyf28Wg@mail.gmail.com>

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You can try [[ -v ${varname:1} ]] and (( $+parameters[${varname:1}] )).

${varname:1} removes the leading plus. If you can change your code so that
the plus isn't added, it gets simpler.

Roman.

On Mon, May 27, 2019 at 9:46 PM Sebastian Gniazdowski <
sgniazdowski@gmail.com> wrote:

> Hello,
> simple test:
>
> a=1
> varname='+a'
> echo ${(P)varname}
>
> yields empty output. Is there any way to use the $+var syntax with (P)
> flag?
>
> --
> Sebastian Gniazdowski
> News: https://twitter.com/ZdharmaI
> IRC: https://kiwiirc.com/client/chat.freenode.net:+6697/#zplugin
> Blog: http://zdharma.org
>

  reply	other threads:[~2019-05-27 19:53 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2019-05-27 19:45 Sebastian Gniazdowski
2019-05-27 19:52 ` Roman Perepelitsa [this message]
2019-05-31 11:00   ` Sebastian Gniazdowski

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