From: Moritz Bunkus <moritz@bunkus.org>
To: zsh-workers@zsh.org
Subject: replace-regex widget not replacing semicolons
Date: Tue, 11 Jun 2013 14:49:42 +0200 [thread overview]
Message-ID: <CANPayMR2TPcxOz-GY6kQYuXongGMy5W_d255y7JZn2_Z+dg3CQ@mail.gmail.com> (raw)
Hey,
I'm using replace-regex bound to ALT+r, and it usually works quite
well. Today I noticed that it doesn't replace semicolons, though. It
looks like an off-by-one error when removing the char from the buffer.
For example, when I enter
$ asd ; qwe
and replace ; by any single char (e.g. "+") then the line stays
exactly as it is.
However, if I try to replace it by two or more chars (e.g. "&&") then
one of the replaced chars is missing and the semicolon stays in its
place, like this:
$ asd &; qwe
How to reproduce:
chai-latte$ zsh --norcs
chai-latte% autoload regexp-replace
chai-latte% autoload replace-string
chai-latte% zle -N replace-regex replace-string
chai-latte% bindkey "^[r" replace-regex
chai-latte% asd ; qwe
Now hit ALT+r, enter ; and &&, see the output changed to:
chai-latte% asd &; qwe
Kind regards,
mosu
next reply other threads:[~2013-06-11 12:49 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2013-06-11 12:49 Moritz Bunkus [this message]
2013-06-11 17:07 ` Bart Schaefer
2013-06-12 6:46 ` Moritz Bunkus
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