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Date: Tue, 11 Jun 2013 14:49:42 +0200
Message-ID: <CANPayMR2TPcxOz-GY6kQYuXongGMy5W_d255y7JZn2_Z+dg3CQ@mail.gmail.com>
Subject: replace-regex widget not replacing semicolons
From: Moritz Bunkus <moritz@bunkus.org>
To: zsh-workers@zsh.org
Content-Type: text/plain; charset=UTF-8

Hey,

I'm using replace-regex bound to ALT+r, and it usually works quite
well. Today I noticed that it doesn't replace semicolons, though. It
looks like an off-by-one error when removing the char from the buffer.
For example, when I enter

$ asd ; qwe

and replace ; by any single char (e.g. "+") then the line stays
exactly as it is.

However, if I try to replace it by two or more chars (e.g. "&&") then
one of the replaced chars is missing and the semicolon stays in its
place, like this:

$ asd &; qwe

How to reproduce:

chai-latte$ zsh --norcs
chai-latte% autoload regexp-replace
chai-latte% autoload replace-string
chai-latte% zle -N replace-regex replace-string
chai-latte% bindkey "^[r" replace-regex
chai-latte% asd ; qwe

Now hit ALT+r, enter ; and &&, see the output changed to:

chai-latte% asd &; qwe

Kind regards,
mosu