From: DervishD <raul@viadomus.com>
To: Zsh <zsh-workers@sunsite.dk>
Subject: Bad expansion
Date: Mon, 21 Jan 2002 15:56:41 +0100 [thread overview]
Message-ID: <E16SfsH-00017M-00@DervishD.viadomus.com> (raw)
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Hello all :))
I have a doubt with parameter expansion, because I'm getting an
error of 'bad substitution' on the following code
# Let's assume I have the following array
testing=(one two three)
export testing
export one_VALUE=DD
# The following line correctly outputs 'one_VALUE'
echo $testing[1]_VALUE
# Idem
echo ${testing[1]}_VALUE
# Bad substitution
echo ${${testing[1]}_VALUE}
The problem is that I will need even further expansion, because I
want to do 'echo ${(P)${testing[1]}_VALUE}', that is, I want the
output of one_VALUE. And, because the rest of the script, I cannot
use directly the value of one_VALUE in the array 'testing'.
What am I doing wrong? Just in case, I want to do what is
achieved under Bash with ${!${testing[0]}_VALUE}. Please note that
arrays start at 0 under Bash, not at 1.
Thanks a lot in advance
Raúl
next reply other threads:[~2002-01-21 14:44 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2002-01-21 14:56 DervishD [this message]
2002-01-21 14:51 ` Zefram
2002-01-21 17:12 ` Bart Schaefer
2002-01-21 19:40 DervishD
2002-01-21 19:46 ` DervishD
2002-01-21 21:31 ` Bart Schaefer
2002-01-22 0:17 DervishD
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