Re: Test Failures Latest CVS

[Peter Stephenson <pws@csr.com>]

Peter Stephenson wrote:
> "Bart Schaefer" wrote:
> > The question is, -should- it have been changed?
> > ... difficult to understand ...
> > ... This seems backwards to me. ...
> > ... always before it has been the case ...
> ... real bug ...
> ... removing that patch. ...

OK, have I got the description right this time?

Index: Doc/Zsh/expn.yo
===================================================================
RCS file: /cvsroot/zsh/zsh/Doc/Zsh/expn.yo,v
retrieving revision 1.31
diff -u -r1.31 expn.yo
--- Doc/Zsh/expn.yo	2001/07/06 09:03:48	1.31
+++ Doc/Zsh/expn.yo	2001/07/06 09:49:17
@@ -791,10 +791,26 @@
 This only applies when searching for substrings, either with the tt(S)
 flag, or with tt(${)...tt(/)...tt(}) (only the var(expr)th match is
 substituted) or tt(${)...tt(//)...tt(}) (all matches from the
-var(expr)th on are substituted).  The var(expr)th match is counted
-such that there is either one or zero matches from each starting
-position in the string, although for global substitution matches
-overlapping previous replacements are ignored.
+var(expr)th on are substituted).  The default is to take the first match.
+
+The var(expr)th match is counted such that there is either one or zero
+matches from each starting position in the string, although for global
+substitution matches overlapping previous replacements are ignored.  With
+the tt(${)...tt(%)...tt(}) and tt(${)...tt(%%)...tt(}) forms, the starting
+position for the match moves backwards from the end as the index increases,
+while with the other forms it moves forward from the start.
+
+Hence with the string
+example(which switch is the right switch for Ipswich?)
+substitutions of the form
+tt(${)LPAR()tt(SI:)var(N)tt(:)RPAR()tt(string#w*ch}) as var(N) increases
+from 1 will match and remove `tt(which)', `tt(witch)', `tt(witch)' and
+`tt(wich)'; the form using `tt(##)' will match and remove `tt(which switch
+is the right switch for Ipswich)', `tt(witch is the right switch for
+Ipswich)', `tt(witch for Ipswich)' and `tt(wich)'. The form using `tt(%)'
+will remove the same matches as for `tt(#)', but in reverse order, and the
+form using `tt(%%)' will remove the same matches as for `tt(##)' in reverse
+order.
 )
 item(tt(M))(
 Include the matched portion in the result.

-- 
Peter Stephenson <pws@csr.com>                  Software Engineer
CSR Ltd., Unit 300, Science Park, Milton Road,
Cambridge, CB4 0XL, UK                          Tel: +44 (0)1223 392070


**********************************************************************
The information transmitted is intended only for the person or
entity to which it is addressed and may contain confidential 
and/or privileged material. 
Any review, retransmission, dissemination or other use of, or
taking of any action in reliance upon, this information by 
persons or entities other than the intended recipient is 
prohibited.  
If you received this in error, please contact the sender and 
delete the material from any computer.
**********************************************************************