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To: Zsh hackers list <zsh-workers@zsh.org>
From: Martijn Dekker <martijn@inlv.org>
Subject: [Bug] Exiting shell from function called by trap handler always
 produces status 0
Message-ID: <a5934536-7982-c434-d98d-2c07d66b0739@inlv.org>
Date: Mon, 8 Oct 2018 14:02:23 +0100
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When a trap handler exits the shell using the 'exit' command within a 
function, the shell's exit status is zero even if another exit status 
was given as an argument to the 'exit' command.

$ Src/zsh -c 'fn() { exit 13; }; trap "fn" EXIT'
$ echo $?
0
(expected output: 13)

I was able to reproduce this in zsh 5.4.1 and up, and not in 5.3.1 and 
earlier. Every other shell also exits with status 13.

Looping through git commits starting from zsh-5.3.1, I found the commit 
that introduced this: d7110d8 (41012: Fix premature exit from nested 
function in EXIT trap).

Thanks,

- M.