From: Martijn Dekker <martijn@inlv.org>
To: Zsh hackers list <zsh-workers@zsh.org>
Subject: [bug] shift: shell exits with status 0 on bad math expression
Date: Wed, 20 Jun 2018 09:45:36 +0100 [thread overview]
Message-ID: <eceefa15-738b-2800-9865-4b3af2b6fb80@inlv.org> (raw)
When an argument is given to 'shift' that constitutes a bad math
expression, the (sub)shell prints an error and exits, but the exit
status is zero (= success) under most conditions.
$ zsh -c 'shift @/@'; echo $?
zsh:1: bad math expression: illegal character: @
0
$ zsh -c 'builtin shift @/@'; echo $?
zsh:1: bad math expression: illegal character: @
0
$ zsh -c 'emulate sh; shift @/@'; echo $?
zsh:1: bad math expression: illegal character: @
1
$ zsh -c 'emulate sh; command shift @/@'; echo $?
zsh:1: bad math expression: illegal character: @
0
The exit status should be non-zero in all cases.
The behaviour is the same from current git down to zsh 5.0.7, the
earliest version I tested.
- M.
next reply other threads:[~2018-06-20 8:59 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
[not found] <CGME20180620090022epcas1p4700aca92f8b52c669c5ac10165a6ce80@epcas1p4.samsung.com>
2018-06-20 8:45 ` Martijn Dekker [this message]
2018-06-20 9:12 ` Peter Stephenson
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