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Subject: Re: f() { local -ar path=(/bin); };f gives an error
To: zsh-workers@zsh.org
References: <20171126232101.GA8393@chaz.gmail.com>
 <7a5807b1-0c5e-8134-a651-83e8b3df4d82@gmx.com>
 <20171127201721.GA1897@chaz.gmail.com>
From: Eric Cook <llua@gmx.com>
Message-ID: <ff7d1972-7eec-2f0c-97bd-d1e958ae3cdd@gmx.com>
Date: Mon, 27 Nov 2017 16:03:00 -0500
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On 11/27/2017 03:17 PM, Stephane Chazelas wrote:
> 
> Thanks.
> 
> But that creates a non-special local "path" variable.
> 
> The issue here is that when you're trying to make $path (the
> special array variable tied to $PATH) readonly (with a value)
> locally in a function, that doesn't work.
> 

That wasn't really asked by your original link. While not common, people do
ask in #zsh why after attempting to use an local (non-readonly)
variable named path to reference an filename or something, they can no longer
execute commands. Using typeset's -h option to hide the special attribute allows
them to do so, so setting it `42' like in the stackexchange link would work
without breaking other stuff.

But to actually allow what you are now asking, I'll defer to someone else.