From: "Jean Bénabou" <jean.benabou@wanadoo.fr>
To: Paul Levy <P.B.Levy@cs.bham.ac.uk>
Cc: Categories <categories@mta.ca>
Subject: R A brief survey of cartesian functors
Date: Fri, 1 Aug 2014 14:10:34 +0200 [thread overview]
Message-ID: <5E8053EE-A599-4E2D-A4D0-B4D937A836FA@wanadoo.fr> (raw)
In-Reply-To: <0453F381-BF68-4CFC-8FD6-6A3B62D3529D@cs.bham.ac.uk>
Dear Paul,
I have received many mails concerning the posting you mentioned and I try to answer all of them with precision. This takes a lot of time. I shall answer yours, in detail, about the general definition of cartesian functors in terms of disdtributors very soon. But the precise answer shall be a bit long, so please be patient.
All I can say now is that, if P: X --> S is a prefoliation the general definition reduces to the simple one I have given (the proof is not trivial).
Moreover some of the results of the theorem require the assumption that P is a prefoliation. Hardly surprising, if you want to prove stronger results you need stronger assumptions. The ones I make are, in a sense, minimal. You'll have I think noticed that for 7) I need P to be a foliation.
Thanks for your interest. Best regards,
Jean
Le 1 août 2014 à 12:35, Paul Levy a écrit :
>
> On 28 Jul 2014, at 10:54, Jean Bénabou wrote:
>
>> 2) CARTESIAN FUNCTORS
>> Let P: X --> S, P': X' --> S and F: X --> X' be functors such that P = P'F. For every object s of S ,I denote by F_s : X_s --> X'_s the functor induced by F on the fibers.
>> I have a general definition of F being cartesian, without any assumption on P and P' and without any reference to cartesian maps, but it uses distributors in an essential manner.
>
> Please tell us your general definition using distributors.
>
> Do any of the results in your Theorem 2.3 hold in this more general setting?
>
> Paul
>
>> 2.3. THEOREM. If P is a pre foliation, P' arbitrary, and F is cartesian, then:
>> (1) F is faithful every F_s is.
>> (2) F is full iff every F_s is.
>> (3) F is essentially surjective iff every F_s is.
>> (4) F is final iff every F_s is.
>> (5) F is flat iff every F_s is.
>> (6) F has a left adjoint iff every F_s has.
>> If moreover P is a foliation, then
>> (7) F is conservative iff every F_s is.
>
> --
> Paul Blain Levy
> School of Computer Science, University of Birmingham
> +44 121 414 4792
> http://www.cs.bham.ac.uk/~pbl
[For admin and other information see: http://www.mta.ca/~cat-dist/ ]
prev parent reply other threads:[~2014-08-01 12:10 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2014-07-28 9:54 Jean Bénabou
2014-07-28 10:52 ` George Janelidze
[not found] ` <1B862C69106C4B6A83703605D3E6A693@ACERi3>
2014-07-28 11:58 ` Jean Bénabou
[not found] ` <E440B3CD-EE6D-4D17-94A3-C9D59B0DBFA5@wanadoo.fr>
2014-07-29 7:02 ` George Janelidze
[not found] ` <F117DEE8B7664FC783858858AE676310@ACERi3>
2014-07-29 9:16 ` Jean Bénabou
[not found] ` <54F4E17E-FAD3-43D8-89F2-5B9CF1C098D8@wanadoo.fr>
2014-07-29 19:58 ` George Janelidze
[not found] ` <400AFA411832442388CF05F4B409628D@ACERi3>
2014-07-30 1:05 ` Jean Bénabou
2014-07-28 15:32 ` Eduardo J. Dubuc
2014-07-28 15:53 ` Joyal, André
[not found] ` <8C57894C7413F04A98DDF5629FEC90B1DB632C@Pli.gst.uqam.ca>
2014-07-28 17:36 ` Jean Bénabou
2014-08-01 10:35 ` Paul Levy
[not found] ` <0453F381-BF68-4CFC-8FD6-6A3B62D3529D@cs.bham.ac.uk>
2014-08-01 12:10 ` Jean Bénabou [this message]
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