Create the values of a sequence with Lua

Create the values of a sequence with Lua

[Fabrice Couvreur via ntg-context]

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Hi,
The idea is to fill the array with the sequence defined by
p(0) = 0.3 and p(n + 1) = 0.3 + 0.7*p(n)
The problem is that I don't really master Lua but I will learn when I have
some time!
Thanks for your help.
Fabrice

\starttext
\startluacode
context.startxtable({"align={middle,lohi},width=2cm,bodyfont=9pt"})
p = {}
p[0] = 0.3
for i=0,19 do
p[i+1] = 0.3+0.7*p[i]^2 end
context.startxrow()
for i=0,19 do
context.startxcell() context(i) context.stopxcell()
context.startxcell() context(i+1) context.stopxcell()
context.startxcell() context("%0.8f",p[i] ) context.stopxcell()
context.stopxrow()
end
context.stopxtable()
\stopluacode
\stoptext

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Re: Create the values of a sequence with Lua

[Aditya Mahajan via ntg-context]

On Mon, 31 Oct 2022, Fabrice Couvreur via ntg-context wrote:

> Hi,
> The idea is to fill the array with the sequence defined by
> p(0) = 0.3 and p(n + 1) = 0.3 + 0.7*p(n)
> The problem is that I don't really master Lua but I will learn when I have
> some time!
> Thanks for your help.
> Fabrice

You just need to adjust the order in which you are doing things...

    \starttext
    \startluacode
    context.startxtable({"align={middle,lohi},width=2cm,bodyfont=9pt"})
    local p = {}
    p[0] = 0.3
    for i= 0, 19 do
        context.startxrow()
        context.startxcell() context(i) context.stopxcell()
        -- context.startxcell() context(i+1) context.stopxcell()
        context.startxcell() context("%0.8f", p[i]) context.stopxcell()
        context.stopxrow()
        p[i+1] = 0.3 + 0.7*p[i]
    end
    context.stopxtable()
    \stopluacode
    \stoptext


Aditya
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