From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-users@zsh.org
Subject: Re: How to add string to end of each array element without loops
Date: Fri, 25 Mar 2011 15:03:49 -0700 [thread overview]
Message-ID: <110325150350.ZM30913@torch.brasslantern.com> (raw)
In-Reply-To: <9861b13e6828d43041a5b489f016664a.squirrel@gameframe.net>
On Mar 25, 11:32pm, nix@myproxylists.com wrote:
} Subject: How to add string to end of each array element without loops
}
} a=(1 2 3)
} a=(foo$^a[@])
}
} print -l "${(@n)a}"
If $^a[@] works, then you don't need the subscript, either:
a=(foo$^a)
Futhermore you don't need the quotes and (@) in the print expression:
print -l ${(n)a}
} foo1
} foo2
} foo3
}
} I would like to get the following output instead:
}
} 1foo
} 2foo
} 3foo
I'm not understanding what you're asking. Either this is as easy as
a=(1 2 3)
a=(${^a}foo) # braces needed to distinguish $a from $afoo
or you've already got (foo$^a) and you're asking how to change "foo?"
into "?foo" for the whole array
setopt extendedglob
a=(${a/(#b)foo(<->)/$match[1]foo})
or you mean something else entirely. Can you elaborate?
--
next prev parent reply other threads:[~2011-03-25 22:04 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-03-25 21:32 nix
2011-03-25 21:45 ` Mikael Magnusson
2011-03-25 21:47 ` nix
2011-03-25 22:03 ` Bart Schaefer [this message]
2011-03-26 1:37 ` nix
2011-03-26 2:10 ` Bart Schaefer
2011-03-26 2:39 ` nix
2011-03-26 7:14 ` Bart Schaefer
2011-03-26 14:04 ` nix
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