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From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-users@zsh.org
Subject: Re: How to add string to end of each array element without loops
Date: Fri, 25 Mar 2011 15:03:49 -0700	[thread overview]
Message-ID: <110325150350.ZM30913@torch.brasslantern.com> (raw)
In-Reply-To: <9861b13e6828d43041a5b489f016664a.squirrel@gameframe.net>

On Mar 25, 11:32pm, nix@myproxylists.com wrote:
} Subject: How to add string to end of each array element without loops
}
} a=(1 2 3)
} a=(foo$^a[@])
} 
} print -l "${(@n)a}"

If $^a[@] works, then you don't need the subscript, either:

a=(foo$^a)

Futhermore you don't need the quotes and (@) in the print expression:

print -l ${(n)a}

} foo1
} foo2
} foo3
} 
} I would like to get the following output instead:
} 
} 1foo
} 2foo
} 3foo

I'm not understanding what you're asking.  Either this is as easy as

    a=(1 2 3)
    a=(${^a}foo)  # braces needed to distinguish $a from $afoo

or you've already got (foo$^a) and you're asking how to change "foo?"
into "?foo" for the whole array

    setopt extendedglob
    a=(${a/(#b)foo(<->)/$match[1]foo})

or you mean something else entirely.  Can you elaborate?

-- 


  parent reply	other threads:[~2011-03-25 22:04 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2011-03-25 21:32 nix
2011-03-25 21:45 ` Mikael Magnusson
2011-03-25 21:47   ` nix
2011-03-25 22:03 ` Bart Schaefer [this message]
2011-03-26  1:37   ` nix
2011-03-26  2:10     ` Bart Schaefer
2011-03-26  2:39       ` nix
2011-03-26  7:14         ` Bart Schaefer
2011-03-26 14:04           ` nix

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