compadd and an array parameter

compadd and an array parameter

[DervishD]

    Hi all :)

    I'm playing (again) with the completion code, and I've written
something like this:

    bindkey "^O" completer
    zle -C completer expand-or-complete completer

    function completer () {

        [[ $compstate[context] = "command" ]] && compadd ${commands##*/}
        return 0

    }

    Well, what I want is to complete using the contents of the
'commands' array, but with the path stripped, but I think that the
compadd command above will lead to a very big expansion. Can I tell
compadd something like 'compadd -a commands' and something more to
make it strip the path or the expansion above is the only way?

    Of course, I could examine 'CURRENT', perform a match and include
only that match in the compadd command line, but I'm curious...

    Thanks a lot in advance :)

    Raúl Núñez de Arenas Coronado

-- 
Linux Registered User 88736
http://www.dervishd.net & http://www.pleyades.net/

Re: compadd and an array parameter

[DervishD]

    Hi all :)

    My excuses again for self-replying...

 * DervishD <zsh@dervishd.net> dixit:
[...]
>         [[ $compstate[context] = "command" ]] && compadd ${commands##*/}
[...]
>     Well, what I want is to complete using the contents of the
> 'commands' array, but with the path stripped, but I think that the
> compadd command above will lead to a very big expansion. Can I tell
> compadd something like 'compadd -a commands' and something more to
> make it strip the path or the expansion above is the only way?

    Better 'compadd -k commands'. The keys of the 'commands'
associative array are the command names, without path. I don't know
what I was thinking...

    Sorry for the noise. What a day...

    Raúl Núñez de Arenas Coronado

-- 
Linux Registered User 88736
http://www.dervishd.net & http://www.pleyades.net/