Howto to print ENTER to zle-buffer?

Howto to print ENTER to zle-buffer?

[Andy Spiegl]

Hi, I want to run a command put something like this at the end of my .zshrc:

  print -z "command-to-run args"
  zle accept-line

But I get the (understandable) error:
 /home/andy/.zshrc:zle:822: widgets can only be called when ZLE is active

Can zsh be told somehow to "press enter"?

Thanks a lot,
 Andy

Re: Howto to print ENTER to zle-buffer?

[Bart Schaefer]

On Dec 13,  4:01pm, Andy Spiegl wrote:
}
}   print -z "command-to-run args"
}   zle accept-line
} 
} Can zsh be told somehow to "press enter"?

If you're doing this in a startup file, you probably want

    print -S "command-to-run args"
    command-to-run args

That is, explicitly place the command into the history, and then run
it directly.

If for some reason you really need the command executed within ZLE,
you will have to create a zle-line-init widget that will accept the
line and then remove or update itself that so it doesn't run it a
second time.

Re: Howto to print ENTER to zle-buffer?

[Andy Spiegl]

> If for some reason you really need the command executed within ZLE,
Actually, yes.  It's for sort of a session-management I'm trying to write.

> you will have to create a zle-line-init widget that will accept the
> line and then remove or update itself that so it doesn't run it a
> second time.
Uffda, sounds complicated.  Could you help me with that a bit, please?

Thanks so much!
 Andy

-- 
 If riding in an airplane is flying, then riding in a boat is swimming.

Re: Howto to print ENTER to zle-buffer?

[Bart Schaefer]

On Dec 13,  5:47pm, Andy Spiegl wrote:
}
} > If for some reason you really need the command executed within ZLE,
} Actually, yes.  It's for sort of a session-management I'm trying to write.

Usually better if you say stuff like this up front, it helps to have
context when trying to answer a question!

Given this -- and assuming you can target zsh-5.3 -- I'd go with:

autoload -Uz add-zle-hook-widget
session-startup {
  command-to-run args	# your thing here
  add-zle-hook-widget -d line-init $WIDGET
}
add-zle-hook-widget line-init session-startup

Re: Howto to print ENTER to zle-buffer?

[Andy Spiegl]

> Usually better if you say stuff like this up front, it helps to have
> context when trying to answer a question!
You are right, sorry.  I had thought about it but then didn't want to
clutter up my (presumably) simple question with too much side information.

> Given this -- and assuming you can target zsh-5.3 -- I'd go with:
I'm still stuck with 5.2.  Guess I have to wait a while then. :-(

> autoload -Uz add-zle-hook-widget
> session-startup {
>   command-to-run args	# your thing here
>   add-zle-hook-widget -d line-init $WIDGET
> }
> add-zle-hook-widget line-init session-startup
Looks very smart but I'm not sure I understand how this works.
You define the function "session-startup" which is then hooked
to zle such that it is run after initialization?  How does it show
up in the zle buffer then?  No "print -z" anymore?

Thanks!
 Andy

Re: Howto to print ENTER to zle-buffer?

[Bart Schaefer]

On Dec 13,  8:29pm, Andy Spiegl wrote:
} Subject: Re: Howto to print ENTER to zle-buffer?
}
} > Given this -- and assuming you can target zsh-5.3 -- I'd go with:
} I'm still stuck with 5.2.  Guess I have to wait a while then. :-(

No, it can still be done; you'll just have to be sure that your
zle-line-init widget doesn't conflict with one the user already has.

Actually if you grab Functions/Misc/add-zle-hook-widget from 5.3 and
make it part of your session manager, it should work in 5.2.

} You define the function "session-startup"

Which I typo'd, I left out the () between the function name and the
open brace ...

} which is then hooked
} to zle such that it is run after initialization?  How does it show
} up in the zle buffer then?  No "print -z" anymore?

I won't show up in the ZLE buffer, instead it will just execute at
the time zle starts up.  I don't know why you'd need it to appear in
the buffer if it's just going to be accept-line'd immediately, but
you can do that like this:

session-startup() {
  zle -U $'command-to-run args\n'
  add-zle-hook-widget -d line-init $WIDGET
}

To "backport" that to 5.2 without add-zle-hook-widget:

zle-line-init() {
  if [[ -n $functions[session-startup] ]]
  then
    session-startup
    unfunction session-startup
  fi
  # Do whatever the user's zle-line-init did
}
zle -N zle-line-init

session-startup() {
  zle -U $'command-to-run args\n'
}

Re: Howto to print ENTER to zle-buffer?

[Andy Spiegl]

Hi Bart,

> No, it can still be done; you'll just have to be sure that your
> zle-line-init widget doesn't conflict with one the user already has.

You are the BEST!  So cool, now it works just as I want it.
Thanks so much!!!

> I don't know why you'd need it to appear in the buffer if it's just
> going to be accept-line'd immediately, ...
Because I want these shells to look exactly the way it looked before it
was closed.  Sometimes keep shells open as a reminder - with the last
executed command visible.

Thanks a lot!
 Andy

Re: Howto to print ENTER to zle-buffer?

[Bart Schaefer]

On Dec 15,  7:20pm, Andy Spiegl wrote:
}
} > I don't know why you'd need it to appear in the buffer if it's just
} > going to be accept-line'd immediately, ...
} Because I want these shells to look exactly the way it looked before it
} was closed.  Sometimes keep shells open as a reminder - with the last
} executed command visible.

Hmm, be careful with that -- if the last executed command was something
destructive, like "rm" or an output redirection, re-executing it might
clobber the wrong thing.