From: nix@myproxylists.com
To: "Mikael Magnusson" <mikachu@gmail.com>
Cc: zsh-users@zsh.org
Subject: Re: A hyphen bug or not?
Date: Fri, 18 Mar 2011 19:21:00 +0200 [thread overview]
Message-ID: <9d2a9fce17a22ad2827daf41f5cd0650.squirrel@gameframe.net> (raw)
In-Reply-To: <AANLkTimBkrj=PFb4XTdNarrnH=0nKERw-JTxQ3HcZ0GQ@mail.gmail.com>
> On 18 March 2011 15:15, <nix@myproxylists.com> wrote:
>> #!/bin/zsh
>>
>> emulate zsh
>>
>> R="-"
>>
>> echo "$R" # <--- its empty here as well !
>>
>> R=$(echo "$R" | base64)
>> R=$(print ${R//$'\n'})
>>
>> echo "R: $R" # <--- this is wrong, it should be a hyphen -
>>
>> # When we change the "R" variable to a octal presentation of hyphen
>>
>> R="\055"
>> R=$(echo "$R" | base64)
>> R=$(print ${R//$'\n'})
>>
>> echo "R: $R" # <--- now it works and base64 decod returns a hyphen "-"
>> as
>> it should.
>>
>>
>> How I can echo a hyphen without echoing octal?
>
> Your problem is that echo actually interprets options, if you want to
> echo arguments starting with a hyphen you should use echo - "arguments
> here" (it's always safe to add the leading hyphen to separate options
> from arguments). If you also don't want to interpret escapes, use echo
> -E - "arguments here".
>
> --
> Mikael Magnusson
>
R="-"
echo - "$R" did the trick.
Thank you.
prev parent reply other threads:[~2011-03-18 17:21 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-03-18 14:15 nix
2011-03-18 14:32 ` Mikael Magnusson
2011-03-18 17:21 ` nix [this message]
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