From: Vincent Lefevre <vincent@vinc17.net>
To: zsh-workers@zsh.org
Subject: "set -e" handling is broken with zsh 5.3.1 and 5.4.1
Date: Sun, 27 Aug 2017 02:50:40 +0200 [thread overview]
Message-ID: <20170827005040.GA12622@zira.vinc17.org> (raw)
Consider:
----------------------------------------
#!/usr/bin/env zsh
set -e
f()
{
[[ -z 1 ]] && false
}
if false; then
:
else
f
echo Fail 1
echo Fail 2
f
echo Fail 3
fi
----------------------------------------
With
zsh 5.3.1-4+b1 under Debian/stretch
zsh 5.4.1-1 under Debian/unstable
I get:
% ./cond2-e; echo $?
Fail 1
Fail 2
1
I suppose that cond2-e should die just after f is called, before
outputting anything. At least, the behavior is not consistent.
zsh 5.0.7 was outputting:
Fail 1
Fail 2
Fail 3
but I suppose that this was incorrect (different from what other
shells give on similar POSIX code).
--
Vincent Lefèvre <vincent@vinc17.net> - Web: <https://www.vinc17.net/>
100% accessible validated (X)HTML - Blog: <https://www.vinc17.net/blog/>
Work: CR INRIA - computer arithmetic / AriC project (LIP, ENS-Lyon)
next reply other threads:[~2017-08-27 1:00 UTC|newest]
Thread overview: 8+ messages / expand[flat|nested] mbox.gz Atom feed top
2017-08-27 0:50 Vincent Lefevre [this message]
2017-08-27 1:30 ` Daniel Shahaf
2017-08-27 1:46 ` Vincent Lefevre
2017-08-27 18:56 ` Peter Stephenson
2017-08-27 22:26 ` Vincent Lefevre
2017-08-28 1:25 ` Daniel Shahaf
2017-08-28 6:45 ` Bart Schaefer
2017-08-28 20:56 ` Peter Stephenson
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