From: Stephane Chazelas <stephane@chazelas.org>
To: Michael Greenberg <michael@greenberg.science>
Cc: zsh-workers@zsh.org
Subject: Re: `return` does not behave properly under `!`
Date: Wed, 7 Dec 2022 08:42:55 +0000 [thread overview]
Message-ID: <20221207084255.ykkg6cgzn4nqc73f@chazelas.org> (raw)
In-Reply-To: <m2a640qtt8.fsf@greenberg.science>
2022-12-06 13:18:59 -0500, Michael Greenberg:
[...]
> i() {
> ! return 9
> echo fail not
> }
> i
> echo $?
> ```
[...]
> 0
[...]
That:
! return n
Behaves like return !n (and ! return behave like return !$? (or
return "$(( ! $? ))" in POSIX syntax) doesn't sound totally off
to me. As written, I would say the POSIX spec may even be
requiring it.
That's consistent with ! break causing the while/until loop it's
in returning with failure which I've seen code rely upon (AFAIK,
that's the only way to get those loops to return with failure;
doesn't work in pdksh and derivatives though).
--
Stephane
next prev parent reply other threads:[~2022-12-07 8:43 UTC|newest]
Thread overview: 14+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-12-06 18:18 Michael Greenberg
2022-12-07 4:53 ` Bart Schaefer
2022-12-07 8:42 ` Stephane Chazelas [this message]
2022-12-07 15:05 ` Michael Greenberg
2022-12-07 16:01 ` Stephane Chazelas
2022-12-07 16:16 ` Peter Stephenson
2022-12-07 17:06 ` Bart Schaefer
2022-12-07 17:21 ` Peter Stephenson
2022-12-07 18:51 ` Bart Schaefer
2022-12-07 17:10 ` Michael Greenberg
2022-12-09 15:22 ` Michael Greenberg
2022-12-09 16:21 ` Bart Schaefer
2022-12-09 19:20 ` Michael Greenberg
2022-12-07 16:08 ` Bart Schaefer
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