nameref and argv

nameref and argv

[Stephane Chazelas]

$ ./Src/zsh -c 'f() { nameref a=argv; g x y; }; g() { echo $a; }; f a b 
c'
x y

I was expecting to see "a b c" there like in:

$ ./Src/zsh -c 'f() { local args=(a b c); nameref a=args; g}; g() { 
local args=(x y); echo $a; }; f'
a b c

-- 
Stephane

Re: nameref and argv

[Bart Schaefer]

On Tue, Nov 21, 2023 at 2:27 AM Stephane Chazelas <stephane@chazelas.org> wrote:
>
> $ ./Src/zsh -c 'f() { nameref a=argv; g x y; }; g() { echo $a; }; f a b c'
> x y
>
> I was expecting to see "a b c" there

Although argv acts like a local, it's actually a global special, so
you always get the special behavior even when accessing through a
nameref.

I thought I'd mentioned this somewhere in the doc but perhaps not.

Underneath, argv ends up being a pointer into the C stack, so there's
no way to get a reference to it from a called function up to the
caller.