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From: Sebastian Gniazdowski <sgniazdowski@gmail.com>
To: Zsh hackers list <zsh-workers@zsh.org>
Subject: (z) flag little crazy when '((' closed with *single* ')'
Date: Mon, 28 May 2018 16:43:58 +0200	[thread overview]
Message-ID: <CAKc7PVA1bDLRsFiZgukbuY+KaD-vAaSMLpNsPzPQt15H4L89Fw@mail.gmail.com> (raw)

Hello,
so how is (( ... )) splitted by (z)?

~ buf='(( i = 1, i <= size, ++ i ))'; printf "|%s|\n" "${(z)buf}"
|(( i = 1, i <= size, ++ i ))|

~ buf='(( i = 1, i <= size, ++ i'; printf "|%s|\n" "${(z)buf}"
|(( i = 1, i <= size, ++ i|

OK, but look what happens when there is single ')', not 0, not 2, but
1 closing parenthesis:

~ buf='(( i = 1, i <= size, ++ i )'; printf "|%s|\n" "${(z)buf}"
|(|
|(|
|i|
|=|
|1,|
|i|
|<|
|=|
|size,|
|++|
|i|
|)|

It splits almost char by char. I wonder if this couldn't be fixed? So
that (z) would split this as:

|(( i = 1, i <= size, ++ i )|

-- 
Best regards,
Sebastian Gniazdowski


             reply	other threads:[~2018-05-28 14:44 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2018-05-28 14:43 Sebastian Gniazdowski [this message]
2018-05-28 17:02 ` Jun T.
2018-05-29  0:08   ` Bart Schaefer

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