From: Sebastian Gniazdowski <sgniazdowski@gmail.com>
To: Zsh hackers list <zsh-workers@zsh.org>
Subject: [BUG?] Very strange behavior, execution of a function is interrupted
Date: Sat, 1 Sep 2018 00:01:58 +0200 [thread overview]
Message-ID: <CAKc7PVCfFXZuEVd510JJLKQ6g0kDC7KRDBmR+=36CcOUceDquQ@mail.gmail.com> (raw)
Hello,
it's quite a lost game to explain this, but I'll try:
- there is a scheduler called from sched +1 and once from zle -F
- it detects timed-out tasks, moves them to ZPLG_RUN, then executes
them reading them from this array
Problem: sometimes execution never reaches this line and beyond:
https://github.com/zdharma/zplugin/blob/7a24478e5862a1359b6cfb2887a792213be07e3a/zplugin.zsh#L1485
Some cycles of the preceding loop are then also skipped.
I feel very helpless in explaining this, maybe there's standard
questions sheet for situation where bug in exec.c is suspected?
I know `break 2' inside a function will break out of loop that
contains the function call. But I don't know what could exit a
function. I have debug prints and observe this clearly. At the
mentioned line, no execution occurs, ZPLG_RUN isn't cleared, I get to
run some tasks twice.
Twice when I checked, it was happening when zle -F was called so near
next second, that timeout'd tasks detection included two time slots:
"0" (0 seconds after first precmd, handled by zle -F) and "1" (1
second after first precmd, handled by sched +1).
--
Sebastian Gniazdowski
News: https://twitter.com/ZdharmaI
IRC: https://kiwiirc.com/client/chat.freenode.net:+6697/#zplugin
Blog: http://zdharma.org
next reply other threads:[~2018-08-31 22:02 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2018-08-31 22:01 Sebastian Gniazdowski [this message]
2018-09-01 19:12 ` Sebastian Gniazdowski
2018-09-02 11:53 ` Sebastian Gniazdowski
2018-09-03 8:16 ` Peter Stephenson
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