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From: Cuong Manh Le <cuong.manhle.vn@gmail.com>
To: zsh-workers@zsh.org
Subject: Why zsh chose to be non-compliant in pattern matching
Date: Fri, 26 Feb 2016 08:02:51 +0700	[thread overview]
Message-ID: <CALS7p_eC1W57J671TP5GDpw4=N+__+w4b+a0Gkgaa3swKq76fA@mail.gmail.com> (raw)

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POSIX documentation for pattern matching (
http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_13_01)
said that any quoted characters in pattern will be match literally.

AFAICT, `["!"a]` will match `!` or `a`, most of shell behave like that
except zsh (and also ksh):

case a in ["!"a]) echo 1;; esac


print nothing. While:

case b in ["!"a]) echo 1;; esac


print 1. zsh treats `["!"a]` the same as `[!a]`.

Is there any reason for this behavior?

PS: The full question can be seen here
http://unix.stackexchange.com/q/265431/38906

Thanks.

             reply	other threads:[~2016-02-26  2:57 UTC|newest]

Thread overview: 5+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2016-02-26  1:02 Cuong Manh Le [this message]
2016-02-26  8:43 ` Bart Schaefer
2016-02-29 10:00   ` Cuong Manh Le
2016-02-29 10:27     ` Peter Stephenson
2016-02-29 22:28       ` Martijn Dekker

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