From: Gabor Lukacs <dr.gabor.lukacs@gmail.com>
To: Ross Street <ross.street@mq.edu.au>
Cc: categories@mta.ca
Subject: Re: Enriched adjoint functor theorem?
Date: Mon, 23 May 2011 15:23:35 -0500 (CDT) [thread overview]
Message-ID: <E1QOlby-0004FC-QA@mlist.mta.ca> (raw)
Hi Ross,
On Mon, 23 May 2011, Ross Street wrote:
> By Yoneda, what you are asking for is an isomorphism
>
> x@(a@b) =~ (x@a)@b
You are quite right. The reason that I prefer to seek
[a,[b,c]] =~ [a@b,c]
is because Kelly showed in "Tensor Products in Categories" that the latter
implies associativity, as well as coherence (Theorem 11).
While I understand the structure of [-,-] very well (and for example, I
was able to show that [a,[b,c]] =~ [b,[a,c]]), I do not know much about
the structure of a@b, and I expect its structure to be extremely
complicated.
> In general, I see no way around proving a certain associativity
> constraint invertible.
My question could be rephased as: Is there an extra condition on [-,-],
which can be expressed only using [-,-], that will imply associativity of @ ?
Of course, the alternative way of phrasing this was to seek a
left-V-adjoint for [a,-]. That was the starting point for my question.
Best,
Gabi
[For admin and other information see: http://www.mta.ca/~cat-dist/ ]
next reply other threads:[~2011-05-23 20:23 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-05-23 20:23 Gabor Lukacs [this message]
-- strict thread matches above, loose matches on Subject: below --
2011-05-23 19:56 Ross Street
2011-05-23 8:13 Fred E.J. Linton
2011-05-23 2:51 Gabor Lukacs
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