Re: C-d heuristics

[Ted Stern <stern@cray.com>]

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On Tue, 12 Mar 2002, Dan Christensen wrote:
>
> Attached are two articles of a sort that I receive daily.
> On the first one, if I hit C-d, I get a nice summary buffer
> which uses the Authors field for the From information and
> the Title field for the Subject.  But on the second one
> I get the From information from the (less useful) From
> header, and I get no subject.  Could the heuristics of
> C-d be tweaked to handle the second case better?
>
> I haven't been able to pinpoint why one of the two is
> handled better currently.

I have yet another problem with C-d.

I've subscribed to a mailing list with an option to receive the daily messages
as a digest.

In the basic *Article* buffer, I see each message/rfc822 attachment, and can
buttonize them if I wish, but if I try to use C-d to view the digest, I get
the following error:

Debugger entered--Lisp error: (error "Couldn't request group: No articles in group lists.mscsoftware-1346-ephemeral:lists.mscsoftware-1346")
  signal(error ("Couldn't request group: No articles in group lists.mscsoftware-1346-ephemeral:lists.mscsoftware-1346"))
  error("Couldn't request group: %s" "No articles in group lists.mscsoftware-1346-ephemeral:lists.mscsoftware-1346")
  gnus-group-read-ephemeral-group("nnfolder+private:lists.mscsoftware-1346" (nndoc "nnfolder+private:lists.mscsoftware-1346" (nndoc-address #<buffer  *gnus digest buffer*>) (nndoc-article-type guess)) t nil nil nil ((adapt-file . "/home/users/stern/News/nnfolder+private/lists/mscsoftware/ADAPT")))
  gnus-summary-enter-digest-group(nil)
  call-interactively(gnus-summary-enter-digest-group)

--
Ted
(speaking for himself, not Cray Inc.)


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Subject: msc.nastran digest: March 09, 2002
From: "MSC.NASTRAN Discussion Group digest" <msc.nastran@lists.mscsoftware.com>
Reply-To: "MSC.NASTRAN Discussion Group" <msc.nastran@lists.mscsoftware.com>
Date: Sun, 10 Mar 2002 00:00:24 -0500

MSC.NASTRAN Discussion Group
MSC.NASTRAN Digest for Saturday, March 09, 2002.

1. RE: Heat Transfer of Electric motor
2. RE: Heat Transfer of Electric motor

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Subject: RE: Heat Transfer of Electric motor
From: "sameer mohrir" <sameerdm@hotmail.com>
Date: Sat, 9 Mar 2002 01:14:34 -0500
Reply-To: "MSC.NASTRAN Discussion Group" <msc.nastran@lists.mscsoftware.com>

Hi

Thanks for giving reference for heat transfer coeff. 

I would like to know wether heat loss is related to velocity of fluid and
how it is related


thanks and regards
Sameer D.Mohrir

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Subject: RE: Heat Transfer of Electric motor
From: "sameer mohrir" <sameerdm@hotmail.com>
Date: Sat, 09 Mar 2002 07:28:38 
Reply-To: "MSC.NASTRAN Discussion Group" <msc.nastran@lists.mscsoftware.com>
MIME-Version: 1.0
Content-Type: text/plain; format=flowed

Hi

I will explain u my problem i am facing with analysis of electric motor.
motor of following dimension ID 0.151m and OD 0.18m and length of 0.203m is 
modelled in FEMAP with properties of material with conductiivty of 45w/m2K 
(steel)

Boundary condition applied as follow
Nodal- inside temperature 145 deg. c
and Elemental -convection 25W/m2K at 20deg.C on outside surface of motor

And after solving the problem in MSC Nastran i get 136 deg.C temperature on 
outer surface .But as per standard outside temperature of electric motor 
should be 98 deg.C

So please could you tell us how much velocity of air to be taken to get 
surface temp as 98 deg.C

thanking you

Sameer D.Mohrir


>From: Torfinn.Tobiassen@kongsberg.com
>Reply-To: "MSC.NASTRAN Discussion Group" 
><msc.nastran@lists.mscsoftware.com>
>To: "MSC.NASTRAN Discussion Group" <msc.nastran@lists.mscsoftware.com>
>Subject: [msc.nastran] RE: Heat Transfer of Electric motor
>Date: Fri, 8 Mar 2002 12:06:08 +0100
>
>MSC.NASTRAN Discussion
>Hi
>
>The heat transfer coefficient is related to the Nusselt number by the
>following expression:
>
>h=(k/D)Nu, k=Thermal conductivity, D=diameter, Nu=Nusselt number
>
>Nu can be calculated from the Reynolds and Prandtl numbers.
>
>Pr=0.69, Re=VD/v=8.3E4, V=airspeed, D=Diameter, v=Kinematic viscosity
>
>Nu=0.3+((0.62Re**0.5*Pr**0.33)/((1+(0.4/Pr)**0.67)**0.25))*(1+(Re/282000
>)**0.5, 2E4 < Re < 4E5
>Nu=213.8
>
>You will find the formula in a Heat Transfer textbook (E.g. Heat
>Transfer by A. F. Mills)
>
>Best Regards
>
>Torfinn Tobiassen
>Kongsberg Defence & Aerospace
>
>
>-----Original Message-----
>From: sameerdm@hotmail.com [ mailto:sameerdm@hotmail.com
><mailto:sameerdm@hotmail.com> ]
>Sent: 8. mars 2002 05:21
>To: msc.nastran@lists.mscsoftware.com
>Subject: [msc.nastran] RE: Heat Transfer of Electric motor
>
>
>MSC.NASTRAN Discussion
>Hi
>
>Thanks for your analysis can u please tell me how u have calculated hc
>(heat transfer coeff)
>
>regards
>
>Sameer D.Mohrir
>Pune (India)
>
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