Re: new Mail-Followup-To patch...please take a look...

["Davide G. M. Salvetti" <salve@debian.org>]

>>>>> "PJ" == Paul Jarc <prj@po.cwru.edu> writes:

PJ> '(lambda ...) is equivalent to (lambda ...).

Oh, I really thought that (lambda ...) was equivalent to (function
(lambda ...)), which in turn also has the read syntax #'(lambda ...).

I know '(lambda ...) is the read syntax for (quote (lambda ...)), which
doesn't evaluate the (lambda ...) inside (that being (quote ...)
purpose), and thus doesn't return (function (lambda ...)) like the macro
lambda should do.

Are you really sure that (lambda ...) evaluates to (quote (lambda ...))
rather than to (function (lambda ...))?

Since I was actually quite a bit confused, I tried and byte-compiled
this small file (let's call it «byte-compilation-test.el»):
<======================================================================>
(setq lambda (lambda (x) (1+ x)))

(setq qlambda '(lambda (x) (1+ x)))

(setq flambda #'(lambda (x) (1+ x)))

(defun show-me-this-fact nil
  "Just a test."
  (interactive)
  (dolist (x '(lambda qlambda flambda))
    (message
     "Function: %s.\nByte-compiled: %s."
     (symbol-name x)
     (if (byte-code-function-p (eval x)) "yes" "no"))
    (sit-for 1)))
<======================================================================>
Try it for yourself: save it, byte-compile it, and then type
«M-x load-file byte-compilation-test.elc» and «M-x show-me-this-fact».

Is there anything I don't get?  It has always been a source of
confusion, to me. :-)

Thanks.

-- 
Salve, | <http://www.linux.it/~salve/>
Davide | GNU PG (GPG) Key ID: 939686D5